Question

Evaluate sin^2 19°+sin^2 71°<br />​

Answer 1

Answer:

Solution :

sin² 19° + sin² 71°

= sin² 19° + sin² ( 90 - 19 )°

= sin² 19° + cos² 19°

= 1

Answer 2

sin2 19 +sin2 71

=sin2 19 + cos2 (90-71)  ( sin and cos are complementary angles sin theta =   cos 90-theta)

=sin2 19 + cos2 19

As angle are equal for 19 degree

= h2/hy2 + b2/hy2

= (h2+b2)/hy2

BY pythogora theorem ,( h2 + b2 = hy2)

So.

(h2+b2)/hy2

=hy2/hy2

= 1 (Answer)

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