Math, asked by paddanalokeswari, 1 month ago

EVALUATE SIN^2 60°+3COT60°-TAN^2 60°​

Answers

Answered by kiranmaharana2020
1

Answer:

 {( \frac{ \sqrt{3} }{2}) }^{2}  +  \frac{3}{ \sqrt{3} }   -  { \sqrt{3} }^{2}

 =  \frac{3}{4}  + \frac{3 \sqrt{3} }{3}   - 3

 \frac{3  - 36 + 3 \sqrt{3  \:  } }{12}

  \frac{ - 33 + 3 \sqrt{3} }{12}

 \frac{ - 11 +  \sqrt{3} }{4}

wish it is helpful to you

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