Math, asked by aanchalmaheshwari81, 2 months ago

Evaluate:
sin^2 63° + sin^2 27°/
cos^2 17° + cos^2 73°

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Answers

Answered by amanraj56
4

Step-by-step explanation:

(sin²63° + sin²27°)/cos²17° + cos²73

{sin²63+sin²(90-63)}/cos²(90-73)+cos²73

(sin²63+cos²63)/sin²73+cos²73

1/1

1

#666

Answered by vpvp197
8

sin² 63° + sin² 27° / cos² 17° + cos² 73°

sin ² (90 - 27) + sin² 27° / cos² (90 - 73) + cos ² 73°

cos² 27° + sin² 27° / sin² 73° + cos ² 73°

1/1

= 1

Thus ,

sin² 63° + sin² 27° / sin² 17° + cos² 73° = 1

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