Evaluate ∫ sin 2 x sin 3 x d x ?
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Answer:
(1/2) sin x - (1/10) sin 5 x + c
Step-by-step explanation:
∫ sin 2 x sin 3 x d x
= (1/2) ∫ 2 sin 2 x sin 3 x d x
= (1/2) ∫ (cos x - cos 5 x) d x
[since, 2 sin a sin b = cos (a-b) - cos (a+b)]
= (1/2) sin x - (1/10) sin 5 x + c
where, c is integration constant.
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