Question

Evaluate: sin [ π/3 - sin⁻¹(-1/2)]


CLASS 12TH CBSE MATHEMATICS SAMPLE PAPER 2018-19

Answer 1

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Answer 2

let y=
$y = \sin^{ - 1} ( -\frac{1}{2} ) \\ = > \sin(y) = - \frac{1}{2} \\ = > \sin(y) = - \frac{\pi}{6} = - 30 \\ = > y = - \frac{\pi}{6 } \\ = > \sin ^{ - 1} ( \frac{ - 1}{2} ) = - \frac{\pi}{6} ........(1) \\ = > \sin ( \frac{\pi}{3} - \sin^{ - 1} ( \frac{ - 1}{2} ) ) \\ = > \sin( \frac{180}{3} + \frac{180}{6} )..using(1) \\ = > \sin(30 + 60) \\ = > \sin(90) = 1$
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