Question

Evaluate sin 49/cos 41
$i \: need \: a \: clear \: explaintion$
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Answer 1

Answer:

Class 10th, trigonometric ratios

Step-by-step explanation:

$\frac{ \sin(49) }{ \cos(41) } = \frac{ \sin( 49) }{ \cos(90 - 49) } = \frac{ \sin(41) }{ \sin(41) } ( \: because \: \sin(x) = \cos(90 - x) ) \\ = \frac{1}{1} = 1$

That's the answer.

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