Math, asked by faizalempire2001, 7 months ago

Evaluate sin 49/cos 41
i \: need \: a \: clear \: explaintion

Answers

Answered by harshsharma88494
2

Answer:

Class 10th, trigonometric ratios

Step-by-step explanation:

 \frac{ \sin(49) }{ \cos(41) }  =  \frac{ \sin( 49) }{ \cos(90 - 49) }  =  \frac{ \sin(41) }{ \sin(41) } ( \: because \:  \sin(x)  =  \cos(90 - x) ) \\  =  \frac{1}{1}  = 1

That's the answer.

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