Question

evaluate: sin 58°/cos 32°+tan42°/cot 48°​

Answer 1

Answer:

2

Step-by-step explanation:

sin 58°/cos 32°+tan42°/cot 48°​

= Sin (90 - 32)/Cos32 + Tan (90-48)/Cot48

= Cos32/Cos32 + Cot48/Cot48 (∵ Sin (90 - θ) = Cosθ

                                                         Tan (90-θ) = Cotθ)

= 1 + 1

= 2

Answer 2

Answer:

$\huge \mathfrak \red{solution} \\ \\ A.T.Q \\ \\ \implies \: \frac{sin \: 58 \degree}{cos \: 32 \degree} + \frac{tan \: 42 \degree}{cot \: 48 \degree} \\ \\ \implies \: \frac{sin(90 \degree - 32 \degree)}{cos \: 32 \degree} + \frac{tan(90 \degree - 48 \degree)}{cot \: 48 \degree} \\ \\ \implies \: \frac{cos \: 32 \degree}{cos \: 32 \degree} + \frac{cot \: 48 \degree}{cot \: 48 \degree} \\ \\ \implies \: 1 + 1 \\ \\ \implies \: \: 2 \\ \\ \\ hope \: it \: helps \: u$