Math, asked by bindhu258, 2 months ago

Evaluate:- sin^6 theta - cos^6 theta

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Answered by AB1012
2

Step-by-step explanation:

= sin⁶a- cos⁶a

= (sin²a)³ - (cos²a)³

= (sin²a -cos²a) (sin²a+cos²a+2sin²acos²a)

= (sin²a-cos²a) (1+2sin²acos²a)

= (sin²a-cos²a)(sin4a+cos4a). if a=30⁰

=( 1)(sin4(30)+cos4(30))

= sin120+cos120

=sin(90+30) + cos(90+30)

=cos30+sin30

=√3/2 +1/2

=√3+1/2

=1.732+1/2

=2.7/2

approximately =~ 1

sin⁶a+cos⁶a~=1

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