Evaluate : sin 60° .cos 30°+cos 60° . sin 30°
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Answered by
16
=sin(60+30)=sin90=1,,,this will be the answer
jaffer269:
show me with step by step working
I think it cannot go lengthier now,,,, in 1st step i used the formula sinAcosB+cosAsinB=sin(A+B) and rest u can easily understand
which calss
are you in bro
I am preparing for iit, 12+
hm
you
11th
Answered by
28
Answer:
1
Step-by-step explanation:
Since, sin A = cos ( 90 - A ),
sin 60° . cos 30° + cos 60° . sin 30
= sin 60° . sin ( 90° - 30° ) + cos 60° . cos ( 90° - 30° )
= sin 60° . sin 60° + cos 60° . cos 60°
= sin^2 60° . cos^2 60°
= 1
( as sin^2 A + cos^2 A = 1 )
here,
let those eq.s be eq.1&2
multiply eq.1 by 3 we get,
3x+3y=15..........(3)
by elimination method
3x+3y=15..............(3)
2x-3y=5...............(2)
we'll get
5x=19 , x= 19/5
then put the value of x in any of the eq and you'll get y
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