Math, asked by zainabkhan31, 9 months ago

Evaluate:
sin? 63°+ sin? 27°
cos? 17° + cos73°​

Answers

Answered by Anonymous
9

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 \frac{ {sin}^{2} 63 ° +  {sin}^{2} 27°}{ {cos}^{2}17° + {cos}^{2}73 °  } \\

 \boxed{\red{{sin}^{2}(90 \degree \:  -  \theta)={cos}^{2} \theta  }}

 \boxed{  \red{ {cos }^{2}(90 \degree \:  -  \theta) ={sin}^{2} \theta }}

 \frac{ sin² (90° - 63°)+ cos² 27°}{</p><p>cos(90° - 73°) + {cos }^{2}  73°} \\

\boxed{\red{{sin }^{2}   \theta  +{cos }^{2}   \theta = 1 }}

 \frac{ cos²  \: 27° + sin² \:  27°}{</p><p>{sin }^{2}  73°+ {cos} ^{2}  73°} \\

 \orange{\frac{1}{1}  =1} \\

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