evaluate :
sin^6theta-cos^6theta
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Answer:
( sin²Ф - cos²Ф )( 1 - sinФcosФ )
Step-by-step explanation:
sin⁶Ф can be written as ( sin²Ф )³
cos⁶Ф can be written as ( cos²Ф)³
sin⁶Ф - cos⁶Ф
= ( sin²Ф )³ - ( cos²Ф )³
Use a³ - b³ = ( a - b )( a² + b² + ab )
= ( sin²Ф - cos²Ф )( sin⁴Ф + cos⁴Ф + sin²Фcos²Ф )
Use : a⁴ + b⁴ + a²b² = ( a² + b² )² - a²b²
= ( sin²Ф - cos²Ф )( ( sin²Ф + cos²Ф )² - sin Ф cos Ф )
Use sin²Ф + cos²Ф = 1
= ( sin²Ф - cos²Ф )( 1 - sinФcosФ )
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