Math, asked by swagata1218, 6 months ago

Evaluate : (sin 77°/cos 13°)^2 +(cos 77°/sin 13°)^2 - 2 cos ^2 45°
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Answers

Answered by sriparnaroy40
6

Answer is 1. Hope this helps u.

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Answered by Anonymous
1

Answer:

(sin 77°/cos 13°) ^2 +(cos 77°/sin 13°)^2 - 2 cos ^2 45°

(sin 77°/sin 77°) ^2+(cos 77°/cos 77°) ^2-(1/√2) ^2

(1) ^2+(1) ^2-2×1/2

1+1-1

=1

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