Question

Evaluate sin square 60+2tan 45 -cos square 30

Answer 1

Answer: 2

=sin^2 60 +2tan 45 -cos^2 30

=(root3/2)^ 2+ 2 (1)- (root3/2)^2

= (root3/2)^ 2 -(root3/2)^ 2 +2

=0+2

=2

Answer 2

Answer:

$\sin^2(60)+2\tan 45-\cos^2 (30)=2$

Step-by-step explanation:

To find : Evaluate $\sin^260+2\tan 45-\cos^2 30$

Solution :

Expression

$\sin^2(60)+2\tan 45-\cos^2 (30)$

Using trigonometry values,

$\sin 60=\frac{\sqrt3}{2}$

$\tan 45=1$

$\cos 30=\frac{\sqrt3}{2}$

Substitute the values in the expression,

$\sin^2(60)+2\tan 45-\cos^2 (30)=(\frac{\sqrt3}{2})^2+2(1)-(\frac{\sqrt3}{2})^2$

$\sin^2(60)+2\tan 45-\cos^2 (30)=\frac{3}{4}+2-\frac{3}{4}$

$\sin^2(60)+2\tan 45-\cos^2 (30)=0+2$

$\sin^2(60)+2\tan 45-\cos^2 (30)=2$

Therefore, $\sin^2(60)+2\tan 45-\cos^2 (30)=2$