Question

evaluate sin square 63 degree + sin square 27 degree upon cos square 17 degree + cos square 73 degree

Answer 1

Heya user
Here is your answer !!

( sin ² 63° + sin ² 27° ) / ( cos ² 17° + cos ² 73° )
= { sin ² 63° + sin ² ( 90 - 63 ) ° } / { cos ² 17° + cos ² ( 90 - 17 ) ° }
= ( sin ² 63° + cos ² 63° ) / ( sin ² 17° + cos ² 17° )
= 1 / 1
= 1 ........... ( Answer ) .


Note :

1 ) sin² X + cos² X = 1
2 ) sin X° = cos ( 90 - X )°


Hope it helps !!