Question

evaluate sin squared theta degree + sin square 70 degree

Answer 1

let theeta=A
sinA+sin70
=SinA + Sin(60+10)
=sinA+sin60cos10+sin10cos60
=sinA+√3/2×cos10+sin10/2
=[2sinA+sin10+√3cos10]/2


OR
sinA+sin70
=2sin[(70+A)/2]×cos[(70-A)/2]

I don't think if any more solution is possible!