Question

evaluate :(sin teta + cos teta) square + (cos teta- sin teta) square​

Answer 1

Consider the given equation.

sinθ+cosecθ=2

sinθ+

sinθ

1

=2

sin

2

θ+1=2sinθ

sin

2

θ−2sinθ+1=0

(sinθ−1)

2

=0

sinθ=1

Therefore,

cosecθ=

sinθ

1

=1

Now,

sin

9

θ+cosec

9

θ=(1)

9

+(1)

9

=2

Hence, this is the required result.

Answer 2

Step-by-step explanation:

hey mate!!!.

here's your answer..