evaluate (sin thera + cos theta)square + ( sin theta - cos theta) square
Answers
Answered by
1
Answer:Letme consider theta=x
Step-by-step explanation:
(Sinx+cos x)^2 + (sinx-cosx)^2
=sinx^2 + 2sinxcosx + cosx^2 + sinx^2 - 2sinxcox +cosx^2
=sin^2x +cosx^2 + sinx^2- cosx^2
= 1 + sinx^2- cosx^2
= 1-(cosx^2 - sinx^2)
=1 - cos2x
This is the answer....
Hope it helps
Similar questions