Question

evaluate sin theta/1+cos theta​

Answer 1

Answer:

$\frac{ \sin( \alpha ) }{1 + \cos( \alpha ) } \\ = \frac{ \sin( \alpha ) }{1 + \cos( \alpha ) } \times \frac{1 - \cos( \alpha ) }{1 - cos \alpha } \\ \\ = \frac{ \sin( \alpha ) \times (1 - \cos( \alpha ) }{1 - { \cos( \alpha ) }^{2} } \\ \\ = \frac{ \sin( \alpha ) \times (1 - \cos( \alpha ) }{ { \sin( \alpha ) }^{2} } \\ \\ = \frac{1 - \cos( \alpha ) }{ \sin( \alpha ) }$

Answer 2

Step-by-step explanation:

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