Math, asked by Ange6etyi9ffat, 1 year ago

Evaluate: sin theta cos (90-theta)+cos theta sin (90-theta)

Answers

Answered by Rahil6351
107
cosA,sin(90-A)+sin A,cos(90-A)
Cos A .Cos A + Sin A. Sin A
=Cos^2 A + Sin^2 A
=1
sol=1
Hope it helps...

Answered by mysticd
36

Answer:

Value \: of \: \\</p><p>sin\theta cos(90-\theta)+cos\theta sin(90-\theta)\\=1

Step-by-step explanation:

Value \: of \: \\</p><p>sin\theta cos(90-\theta)+cos\theta sin(90-\theta)

=sin\theta \times sin\theta + cos\theta \times cos\theta

= sin^{2}\theta + cos^{2}\theta

/* We know the Trigonometric identity:

\boxed {sin^{2}\theta+cos^{2}\theta = 1 }*/

= $1$

Therefore,

Value \: of \: \\</p><p>sin\theta cos(90-\theta)+cos\theta sin(90-\theta)\\=1

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