Evaluate sin theta*cos theta-((sin theta*cos(90-theta)*cos theta)/sec(90-theta))-((cos theta*sin(90-theta)*sin theta)/cosec(90-theta))
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hey mate please refer to the attachment
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Step-by-step explanation:
sinθcosθ - sinθcos(90°-θ)cosθ/sec(90°-θ) - cosθsin(90°-θ)sinθ/cosec(90°-θ)
=> cosθsinθ - sinθsinθcosθ/cosecθ - cosθcosθsinθ/secθ
=> cosθsinθ - sin³θcosθ - cos³θsinθ
= cosθsinθ - cosθsinθ(sin²θ + cos²θ)
= cosθsinθ - cosθsinθ
= 0
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