evaluate:(sin0+cos0)2+(cos0-sin0)2
Answers
Answered by
1
Answer:
answer is 2. hope it helps
Answered by
4
Answer:
2
Step-by-step explanation:
(sin0+ cos0)² + (sin0-cos0)²
(sin0+ cos0)² + (sin0-cos0)²= (sin²0 + cos²0 + 2sin0.cos0) + (sin²0 + cos²0 - 2sin0.cos0) [:. using (a+b)²= a²+b²+2ab and (a-b)²=a²+b²-2ab]
=sin²0 + cos²0 + sin²0 + cos²0 + 2sin0.cos0 - 2sin0.cos0
2sin0.cos0=1+1 [:. sin²0+cos²0=1]
=2 (ans)
Hope it helps you!
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