Math, asked by shravan26, 1 year ago

evaluate sin15° sec75°

Answers

Answered by hritikasawant
118
sin15°sec75°
=sin15°(1/cos75°)
=sin15°/cos75°
=sin15°/sin15°...........[ cos(π/2)-75=sin 15°
=1
Answered by tardymanchester
87

Answer:

\sin 15^\circ \sec 75^\circ=1

Step-by-step explanation:

Given : Expression \sin 15^\circ \sec 75^\circ

To evaluate : The given expression ?

Solution :

\sin 15^\circ \sec 75^\circ

=\sin 15^\circ (\frac{1}{\cos 75^\circ})

= \frac{\sin 15^\circ}{\cos 75^\circ}

We know, \cos (90- 75)=\sin 15^\circ

Substitute,

= \frac{\sin 15^\circ}{\sin 15^\circ}

=1

Therefore, \sin 15^\circ \sec 75^\circ=1

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