Question

evaluate sin18/cos72​

Answer 1

Answer:

Sin 18/cos72 cos(90-72)/cos72

Cos72/sin72=1

Tan26/tan(90-74)=1

Cos48-sin42=sin(90-42)-sin42=0

Cosec31-Cosec(90-69)

Cose31-Cosec31=0

Step-by-step explanation:

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Answer 2

Answer:-

$\longrightarrow$$\large\sf{\frac{sin(90°-72°)}{cos72°}}$

$\longrightarrow$$\large\sf{\frac{cos72°}{cos72°}}$

$\longrightarrow$$\huge\sf{1}$