evaluate sin18/cos72 + root3 (tan10 tan30 tan40 tan50 tan80)
Answers
Answered by
1
Sin 18°/cos 72° + √3 [tan10 tan 30 tan 40 tan 50 tan 80]
=Sin 18°/cos(90-72) + √3 [tan10 tan 30 tan 40 tan(90-50) tan(90-80)]
=Sin 18°/Sin 18 + √3 [tan10 tan 30 tan 40 cot40 cot10]
=1 + √3 [tan10 tan 30 tan 40 1/tan40 1/tan10]
=1 + √3 [tan 30]
=1 + √3 [1/√3]
=1 + 1 = 2
Answered by
1
defeat the shortcut 2...........
Similar questions