Math, asked by padmakripavaram1976, 7 months ago

evaluate sin18°/cos 72°



Answer:

sin18°=90-18=72.
cos72°/cos72°= 1​

Answers

Answered by pratapsinghaviral91
0

Answer:

Find an answer to your question Evaluate : (i) sin 18°/cos 72° (ii) tan 26°/cot 64° ... (90° - 36°)/cot 64° = cot 64°/cot 64° = 1(iii) cos 48° - sin 42° = cos (90° - 42°) - sin ... Sin 18/cos72 cos(90-72)/ cos72

Answered by ItzDazzingBoy
0

Answer:

Answer in attachment.........

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