Math, asked by sagarrana49, 1 month ago

Evaluate :
sin18°/cos72°
+ ✓3 tan10° tan30° tan40° tan50° tan80°.​

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Answers

Answered by GlamorousAngel
49

ANSWER :-

{ \bigstar} \:  \:  \:  \sf{Sin 18°/cos 72° + √3 [tan10 \:tan 30\: tan 40\:  tan 50 \: tan 80] }\\  \\  \sf{</p><p></p><p> \implies \: Sin 18°/cos(90-72) + √3 [tan10\: tan 30 \:tan 40\: tan(90-50) \:tan(90-80)]} \\  \\    \sf{</p><p></p><p> \implies \: Sin 18°/Sin 18 + √3 [tan10 \:tan 30 \:tan 40 \:cot40 \:cot10]} \\  \\  \sf{</p><p></p><p> \implies \: 1 + √3 [tan10\: tan 30\: tan 40 \:1/tan40 \:1/tan10]} \\  \\  \sf{</p><p></p><p> \implies \: 1 + √3 [tan 30]}</p><p> \\  \\  \sf{</p><p> \implies \: 1 + √3 [1/√3]} \\  \\  \sf{</p><p></p><p> \implies \: 1 + 1 }  \\  \\   \boxed{ \underline{\sf {\red{ \implies \:  2 \: { \bigstar}}}}}</p><p> </p><p>


BrainlyHero420: Good ❤️
GlamorousAngel: Thnku :)
PageI: why the answer have <\p> tags ??
GlamorousAngel: donno
PageI: mere dost ne bata ki asa isliye hua kyunki aapne sayad last mein [/tex] tag nahi lagaya
Anonymous: Awesome ❤
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