Math, asked by Dish9, 1 year ago

Evaluate:- sin² 25° + sin² 65° + √3 (tan 5° tan 15° tan 30° tan 75° tan 85°)

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Answered by Panzer786
22
Sin²25° + Sin²65° + √3 ( Tan5° × Tan15° × Tan30° × Tan75° × Tan85° ) .



Sin²(90-65° ) + Sin²65° + √3 ( Tan5° × Tan85° × Tan15° × Tan75° × Tan30° ).





Cos² 65° + Sin²65° + √3 ( Tan5° × Tan(90-5°) * Tan15° × Tan(90-15°) * Tan 30° ).




Sin²65° + Cos²65° + √3 ( Tan 5° × Cot5° * Tan15° × Cot15° * 1/√3 ).


Sin²65° + Cos²65° + √3 ( Tan5° × 1/Tan5° * Tan15° × 1/Tan15° × 1/√3 ).



1 + √3 ( 1 * 1 * 1/√3 )


1 + √3 ( 1/√3 )



1 + √3 × 1/√3


1 + 1

2
Answered by chanchiladevi1720
0

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