Math, asked by bhavyagarg8183, 11 months ago

Evaluate:∫sin2(2tan−1√1+x1−x)dx.−1≤x≤1

Answers

Answered by ayushmaancristiano

0

Answer:

Step-by-step explanation:

sin2(2tan−1√1+x1−x)dx.−1≤x≤1

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