Math, asked by nirupamapradhan164, 11 months ago

EVALUATE
(sin25*/cos65*)^2 + (tan65*/cot25*)^2- 2 cos^2 45*

Answers

Answered by poojasharma69732
2

hope it helps you.......

Attachments:
Answered by dna63
2

Answer:

1

Step-by-step explanation:

(sin45°/cos65°)^2+(tan65°/cot25°)^2-2cos^2 45°

={cos(90°-45°)/cos65°}^2+{cot(90°-65°)/cot25°)^2-2×(1/√2)^2

=(cos65°/cos65°)^2+(cot25°/cot25°)^2-2×1/2

=1^2+1^2-1

=1+1-1

=2-1

=1

Hope it helps you

Similar questions