Math, asked by harikadudigani, 9 months ago

evaluate sin30°+ tan45°+cos60°/cot45°+cosec30°-sec60°​

Answers

Answered by ItzArchimedes
123

ANSWER:

 \to \small \rm{ \dfrac{ {sin30}^{ \circ} +  {tan45}^{ \circ} +  {cos60}^{ \circ}   }{  {cot45} ^{ \circ} +  {cosec30}^{ \circ} -  {sec60}^{ \circ}   } }

Using

★ sin30° → 1/2

★ tan45° → 1

★ cos60° → 1/2

★ cot45° → 1

★ cosec30° → 2

★ sec60° → 2

Substitute

 \frac{ \frac{1}{2} + 1 +  \frac{1}{2}  }{1 + 2 - 2}  \to \frac{2}{1}

Hence, sin30°+tan45°+cos60°/cot45°+cosec30°-sec60° = 2


JinKazama1: Your answer must be (1/2+1+1/2)/(1+2-2)=2
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