Question

Evaluate:

sin39°/cos 51°+2 tan 11°tan31°tan45°tan59°tan79°–3(sin²21+sin²69°)

Answer 1

sin39/cos(90-39)2tan79*1*tan31 tan(90-31)tan (90-79)-3{sin^2(90-21)+sin 21}
=sin39/sin39+2tan79 tan31 cot31 cot79 - 3{cos^2(21)+sin^2(21)}
=1+2tan 79 tan 31*(1/tan31) (1/tan79)-3{cos^2(21)+sin^2(21)}
=1+2-3(1)
=3-3
=0

Answer 2

Answer:

it is weong of sp better luck next time