Question

Evaluate sin42-cos48

Answer 1

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$\lll \lll\bold{ \huge{ \underline{ \fbox{ \color{springgreen}{dhanyavaad}}}}} \lll \lll \lll$

$\lll \lll\bold{ \huge{ \underline{ \fbox{ \color{crimson}{be \: brainly}}}}} \lll \lll \lll$

$\: \star \star\lll \lll\bold{ \huge{ \underline{ \fbox{ \color{teal}{yaduvanshi \: king}}}}} \lll \lll \lll \star \star$


Note:- Cos(90-∅)=Sin∅


Now..


Sin42°-cos48°
Sin(90-48∅)-cos48°

Cos48°-cos48∅

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thanks!!

Answer 2

Answer:

0

Step-by-step explanation:

We will use the following rule of complementary to solve this question.

sin A = cos ( 90° - A )

In this question,

A = 42, B = 48

sin 48° - cos 42°

cos ( 90° - 48° ) - cos 42°

cos 42° - cos 42°

0