Math, asked by tsrilaxmi, 10 months ago

evaluate sin⁴thita-cos⁴thita÷sin²thita-cos²thita​

Answers

Answered by nikitatiwari620
0

Answer:

(sin^2)^2-(cos^2)^2/(sin^2-cos^2)

(sin^2-cos^2)(sin^2+cos^2)/(sin^2-cos^2)

=(sin^2+cos^2)

please mark me as brainliest

Similar questions