Question

evaluate sin⁴thita-cos⁴thita÷sin²thita-cos²thita​

Answer 1

Answer:

1

Step-by-step explanation:

• (SIN ^4 A-COS^4 A)/(SIN^2 A - COS^2 A). ( LET THETA = A) We know that. (sin^2A+cos^2A)=1. hence, (1-Cos^2A)^2 - COS^4)/(1-2cos^2A) =(1+cos^4A-2cos^2A-cos^2A)/(1-cos^2 A). =1