Question

Evaluate sin58/cos32+tan42/cot48​

Answer 1

Answer:

2 is the answers.

Step-by-step explanation:

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Answer 2

$\frac{ \sin58°}{ \cos32° } + \frac{ \tan42°}{ \cot48°} \\ = \frac{ \sin(90°- 32°) }{ \cos32°} + \frac{ \tan(90° - 48°) }{ \cot48°} \\ = \frac{ \cos32°}{ \cos32°} + \frac{ \cot48°}{ \cot48°} \\ = 1 + 1 \\ = 2$

Note : sin (90°-A)=cos A

tan(90°-A)=cot A