Question

Evaluate sin60 cos30.what is the value of sin (60+30).what can you conclude?

Answer 1

Answer:

sin60°=√3/2

cos30°=√32

sin60°.cos30°=√3/2*√3/2

=3/4

now,

sin(60+30)=1/2+√3/2

=√3+1/2

hence this is your answer

Answer 2

We know that,

$</strong><strong>\sf \sin60° = \large\frac{ \sqrt{3} }{2}$

$\sf \cos30° = \large\frac{ \sqrt{3} }{2}$

$\sf \sin30° = \large\frac{ {1} }{2}$

$\sf \cos60° = \large\frac{ {1} }{2</strong><strong>}$

$\large \sf = ( \frac{ \sqrt{3} }{2} ) \: ( \frac{ \sqrt{3} }{2} ) \: + ( \frac{ {1} }{2} ) \: ( \frac{ {1} }{2} )$

$\large \sf= \frac{3}{4} + \frac{1}{4}$

$\large \sf = \frac{ \cancel{4}}{ \cancel{4}}$

$\sf= 1$

$\sf\sin</strong><strong>(</strong><strong>60° + 30°) = 90°$

$\sf </strong><strong> </strong><strong>W</strong><strong>here</strong><strong>,</strong><strong>\sin90° = 1$