Math, asked by rohan207534, 11 months ago

Evaluate :
sin63° + sin? 27°/
COS? 17° + cos2 73°

Answers

Answered by unzilakhan48
6

Answer:

Step-by-step explanation:

  • sin²63°+sin²73°÷cos² 17+cos²73°
  • sin²(90-27)+sin² 27°÷cos²(90-73) + cos² 73°
  • cos² 27° + sin² 27°÷sin² 73°+cos²73
  • 1÷1
  • 1

we know that

63+27=90

Hence,

63=90-27

Similarly

17+73=90

Hence,

17=90-73

cos(90-α) = sinα

& sin(90-α) =cosα

as

cos²A+sin²A=1

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