Question

Evaluate: sinAcosA-sinAcos(90-A)cosA/sec(90-A) -cosAsin(90-A)sinA/cosec(90-A)

Answer 1

Answer:

0

Step-by-step explanation:

sinAcosA - sinA×sinA×cosA/cosecA - cosA×CosA×sinA/secA

[as cos(90-A)=sinA ,  sin(90-A)=cosA , sec(90-A)=cosecA , cosec(90-A)=secA]

= sinAcosA-sin²A×cosA×sinA - cos²A×sinA×cosA

[as 1/cosecA=sinA , 1/secA=cosA]

=sinAcosA-sinAcosA(sin²A+cos²A)

since, sin²A+cos²A=1

∴ans =0