Math, asked by honeythakur3998, 10 months ago

Evaluate sqrt(x^2+y^2) dx dy dz region bounded by z=x^2+y^2

Answers

Answered by nishantsingh34
0

Step-by-step explanation:

that I=∭S(x2+y2+z2)dxdydz=210a5k75(1+k23),a>0,k>0 where S is the region bounded by the cilinder x2+y2=2ax and the upper and lower sections of ...

Top answer · 2 votes

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