Math, asked by anjali20198, 11 months ago

evaluate submittion up-to 11 k=1 (2+3power k)​

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Answered by anujyadav3124
1

Answer:

11k = 1(2 + 3k) \\ 11k = 2 + 3k \\ 11k - 3k = 2 \\ 8k = 2 \\ k =  \frac{2}{8}  \\ k =  \frac{1}{4} .

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