Question

Evaluate:- tan-¹ (1) + cos-¹ (½) + sin-¹(½)
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Answer 1

$\huge{\mathcal{\underline{\red{Answer}}}}$

$\tan {}^{ - 1} (1) + \cos {}^{ - 1} ( \frac{ - 1}{2} ) + \sin{}^{ - 1} ( \frac{ - 1}{2} )$

$= \frac{\pi}{4} + \frac{2\pi}{3} - \frac{\pi}{6} \\ = \frac{3\pi + 8\pi + 2\pi}{12} \\ = \frac{9\pi}{12} \\ = \frac{3\pi}{4}$