Evaluate : tan^-1 1 + tan^-1 2+tan^-1 3
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tan^-1 ( 1 plus 2 / 1- 1x 2) plus tan^-1 3 tan^-1 ( 3 /-1 ) plus tan^-1 3 then, tan^-1 (-3) plus tan^-1 3 & tan^-1 ( -3 plus 3 / 1plus -3x3) -- tan^-1 (0) -- 0
adrockz99p2v3u6:
Answer is pi.
yes
because
tan 180 - 0 & radian form in pie
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