Question

Evaluate tan' (-1) -sin' (-1/2) - cos'(√3/2)​

Answer 1

Step-by-step explanation:

We have,

$\tan^{ - 1} ( - 1) - \sin^{ - 1} \bigg(- \frac{1}{2} \bigg) - \cos^{ - 1} \bigg( \frac{ \sqrt{3}}{2} \bigg)$

$= - \tan^{ - 1} (1) + \sin^{ - 1} \bigg( \frac{1}{2} \bigg) - \cos^{ - 1} \bigg( \frac{ \sqrt{3}}{2} \bigg)$

$= - \frac{\pi}{4} + \frac{\pi}{6} - \frac{\pi}{6}$

$= - \frac{\pi}{4}$