Question

evaluate tan^-1 {sin (- pie/2}evaluate evaluate
$evaluate \: tan^{ - 1} {sin < - \pi \div 2 > }$

Answer 1

$\sin( \frac{-\pi}{2} ) = - 1 \\ { \tan}^{ - 1} ( \sin( \frac{-\pi}{2 } )) \\ = { \tan }^{ - 1} (-1) \\ = \frac{3\pi}{4}$