Math, asked by Anonymous, 8 months ago

Evaluate tan 26°. tan 64​

Answers

Answered by Anonymous
21

\mathtt{\bf{\large{\underline {\red{Given \: question}}}}}

Evaluate :-

tan26° \times tan64° \\

\mathtt{\bf{\large{\underline {\red{Required \: answer}}}}}

 \huge \mathcal \color{maroon}{1}

\huge\color{orange}{\underline{\underline {Solution}}}

\color{blue}{Given, }

tan26° \times tan64° \\

tan26° \:c an \: also \: \: written \: as:- \\ ⟹ tan(90 - 64)°

\color{blue}{We\: know, }

 ❥ \: tan \: (90 -θ ) = cotθ \\

\color{blue}{Here, \: θ = \:64°}

\color{blue}{and}

❥ \: cotθ \times tanθ = 1

\color{blue}{So,}

tan(90 - 64)° \times tan(64)° \\ ⟹   cot64° \times tan64° \\   ⟹ 1

\huge\color{purple}{\underline{\underline {Formula \: used:-}}}

☞ \: tan \: (90 -θ ) = cotθ \\

☞ \: cotθ \:  \times  \: tanθ = 1

Answered by ranaved784
2

Answer:

Requiredanswer

\huge \mathcal \color{maroon}{1}1

\huge\color{orange}{\underline{\underline {Solution}}}Solution

Given,

\begin{gathered}tan26° \times tan64° \\ \end{gathered}tan26°×tan64°

\begin{gathered}tan26° \:c an \: also \: \: written \: as:- \\ ⟹ tan(90 - 64)°\end{gathered}tan26°canalsowrittenas:−⟹tan(90−64)°

\color{blue}{We\: know, }Weknow,

\begin{gathered} ❥ \: tan \: (90 -θ ) = cotθ \\ \end{gathered}❥tan(90−θ)=cotθ

\color{blue}{Here, \: θ = \:64°}Here,θ=64°

\color{blue}{and}and

❥ \: cotθ \times tanθ = 1❥cotθ×tanθ=1

\color{blue}{So,}So,

\begin{gathered}tan(90 - 64)° \times tan(64)° \\ ⟹ cot64° \times tan64° \\ ⟹ 1\end{gathered}tan(90−64)°×tan(64)°⟹cot64°×tan64°⟹1

\huge\color{purple}{\underline{\underline {Formula \: used:-}}}Formulaused:−

\begin{gathered}☞ \: tan \: (90 -θ ) = cotθ \\ \end{gathered}☞tan(90−θ)=cotθ

☞ \: cotθ \: \times \: tanθ = 1☞cotθ×tanθ=1

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