CBSE BOARD X, asked by kirat6468, 9 months ago

Evaluate tan 7° , 23° , 83°
Solve the question

Answers

Answered by AwesomeSoul47
11

Answer:

hey mate your answer

Given, tan7°tan23°tan60°tan67°tan83°

= tan(90°-83°)tan83°tan(90-67°)tan67°tan60°

= cot83°tan83°cot67°tan67°tan60°

= (1/tan83°) × tan83° × (1/tan67°) × tan67°× tan60°

= 1 × 1 × tan60°

= √3 (ans.)

Explanation:

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Answered by Nitinmenon
0
tan 7*x1/tan7*xtan23*=1x tan23*=tan23*
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