Question

Evaluate tan 85 - tan 40 upon 1+tan 85 - tan 40

Answer 1

Answer:

1

Step-by-step explanation:

by using identiti

tan(a-b) = tana-tanb/1+tana×tanb

tan(85-40)= tan85-tan40/1+tan85.tan40

tan45=1

Answer 2

Given: a trigonometric function $\frac{tan85^{o} -tan40^{o} }{1+tan85^{o}tan40^{o}}$.

To find: the value of the given trigonometric function.

Step-by-step explanation:

Step 1 of 1

$\frac{tan85^{o} -tan40^{o} }{1+tan85^{o}tan40^{o}}$ is given.

The trigonometric equation which is given as $tan(a-b)=\frac{tana-tanb}{1+tanatanb}$ can be used to solve this.

Here a = 85 and b =40.

$\frac{tan85^{o} -tan40^{o} }{1+tan85^{o}tan40^{o}}=tan(85-40)\\\\\\\frac{tan85^{o} -tan40^{o} }{1+tan85^{o}tan40^{o}} =tan45\\\\ \frac{tan85^{o} -tan40^{o} }{1+tan85^{o}tan40^{o}}=1$