Evaluate tan A + cot A is equal to 2 ,find tan square A + cot square A
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Given that
tanA + cotA = 2
Squaring both side, we get
(tanA + cotA)² = 4
tan²A + cot²A +2tanAcotA = 4 [ using (a+b)² = a² +b² +2ab ]
tan²A + cot²A +2tanA(1/tanA) = 4 [ since cotA = 1/tanA ]
tan²A + cot²A +2 = 4
tan²A + cot²A = 4 - 2
tan²A + cot²A = 2
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