Question

evaluate tan A+tan B​

Answer 1

Answer:

Given that tanA=1/2,tanB=1/3

tan(A+B)=

1−tanAtanB

tanA+tanB

=

1−(

2

1

)(

3

1

)

2

1

+

3

1

=

6

5

×

5

6

=1

∴tan(A+B)=1=tan45

∘

⇒A+B=45

∘

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Answer 2

Step-by-step explanation:

tanA+ tanB = sinA/cosA + sinB/cosB

=( sinAcosB+sinBcosA) /cosAcosB

=sin(A+B) /cosAcosB

Therefore;-

tanA+ tanB =sin(A+B)/cosAcosB