evaluate tan10 tan15 tan75 tan80
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Since tan(x)=cot(90-x)
So tan10=cot80 , tan15=cot75
So the given equation changes to
tan80cot80tan75cot75....... (1)
Also tanx.cotx=1
So (1)→1×1=1
Hope my ans was easy for you
So tan10=cot80 , tan15=cot75
So the given equation changes to
tan80cot80tan75cot75....... (1)
Also tanx.cotx=1
So (1)→1×1=1
Hope my ans was easy for you
MayankSoni:
Tell me, which step is confusing
It is the given question
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